Answer: We must first know the heat of fusion of water, which is the required energy to melt a given quantity of ice. For water, this is 334 J/g. 334 Joules have to be applied to one gram of 32°F ice to melt it, so 334 Joules have to be taken out of one gram of 32°F water to freeze it.

10 pounds is 4,535.9237 grams, so (4,535.9237) * 334 gives us 1,514,998.52, the amount of energy in Joules that has to be removed from 10 pounds of water to freeze it.

The final answer is 1.51499852 MJ (megajoules)